What is expand (x^2-2x-3)*ln^2(x-1) ?

The solution to expand (x^2-2x-3)*ln^2(x-1) is x^2ln^2(x-1)-2xln^2(x-1)-3ln^2(x-1)

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expand (x^2-2x-3)*ln^2(x-1)

expand

(x^{2} - 2 x - 3) \cdot ln^{2} (x - 1)

x^{2} ln^{2} (x - 1) - 2 x ln^{2} (x - 1) - 3 ln^{2} (x - 1)

Solution steps

(x^{2} - 2 x - 3) ln^{2} (x - 1)

= ln^{2} (x - 1) (x^{2} - 2 x - 3)

Distribute parentheses

= ln^{2} (x - 1) x^{2} + ln^{2} (x - 1) (- 2 x) + ln^{2} (x - 1) (- 3)

Apply minus-plus rules

+ (- a) = - a

= x^{2} ln^{2} (x - 1) - 2 x ln^{2} (x - 1) - 3 ln^{2} (x - 1)

\frac{d}{d t} ((s (t)) (4 t^{2} - 6 t - 5))

(3 y + 15)^{\circ} (3 y + 15) + (2 y + 5)

\frac{12 x ^{2} + 18}{x ( x ^{2} + 4 )}

e^{(x + 2)^{3}}

(x - y) \cdot e^{x - y}

What is expand (x^2-2x-3)*ln^2(x-1) ?
The solution to expand (x^2-2x-3)*ln^2(x-1) is x^2ln^2(x-1)-2xln^2(x-1)-3ln^2(x-1)