What is expand (3n(3n+1))/((3n-1)(3n+2)) ?

The solution to expand (3n(3n+1))/((3n-1)(3n+2)) is (9n^2+3n)/(9n^2+3n-2)

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expand (3n(3n+1))/((3n-1)(3n+2))

expand

\frac{3 n ( 3 n + 1 )}{( 3 n - 1 ) ( 3 n + 2 )}

\frac{9 n ^{2} + 3 n}{9 n ^{2} + 3 n - 2}

Solution steps

\frac{3 n ( 3 n + 1 )}{( 3 n - 1 ) ( 3 n + 2 )}

Expand

(3 n - 1) (3 n + 2) : 9 n^{2} + 3 n - 2

= \frac{3 n ( 3 n + 1 )}{9 n ^{2} + 3 n - 2}

Expand

3 n (3 n + 1) : 9 n^{2} + 3 n

= \frac{9 n ^{2} + 3 n}{9 n ^{2} + 3 n - 2}

2 π (x - 100 t)

\frac{ln ∣ x ∣ + 2 \cdot ( x - 6 ) \cdot x - 1}{x}

g (x) (x = 2 + lo g_{4} (x + 1))

\frac{d}{d s} \frac{1}{( s ( s + 2 ) ^{2} )} \cdot (s + 2)

(2 x - y = 2,) (x + y + 3 = 0)

What is expand (3n(3n+1))/((3n-1)(3n+2)) ?
The solution to expand (3n(3n+1))/((3n-1)(3n+2)) is (9n^2+3n)/(9n^2+3n-2)