What is expand (-4v,-1,2u+1)(0,2,1) ?

The solution to expand (-4v,-1,2u+1)(0,2,1) is -4(0*2*1,,)v,-1*(0*2*1,,),2u+1*(0*2*1,,)

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expand (-4v,-1,2u+1)(0,2,1)

expand

(- 4 v, - 1, 2 u + 1) (0, 2, 1)

- 4 (0 \cdot 2 \cdot 1,,) v, - 1 \cdot (0 \cdot 2 \cdot 1,,), 2 u + 1 \cdot (0 \cdot 2 \cdot 1,,)

Solution steps

(- 4 v, - 1, 2 u + 1) (0, 2, 1)

= (0 \cdot 2 \cdot 1,,) (- 4, v - 1 \cdot 2, u + 1)

Distribute parentheses

= (0, 2, 1) (- 4 v,) + (0, 2, 1) (- 1, 2 u) + (0, 2, 1) \cdot 1

Apply minus-plus rules

+ (- a) = - a

= - 4 (0 \cdot 2 \cdot 1,,) v, - 1 \cdot (0 \cdot 2 \cdot 1,,), 2 u + 1 \cdot (0 \cdot 2 \cdot 1,,)

(v, u + v, 2 u^{2} - 2 v^{2}) \cdot (- 2 u - 4 v, 4 v, 1)

\frac{\partial}{\partial u} ((y) (uv - z (y, u, v)))

\frac{( - 2 x - 3 x ^{2} ) ( 4 - x ^{2} - x ^{3} )}{h}

3 sin (\frac{( π ( x - 5 ) )}{( 6 )})

\frac{1}{( j x + 4 ) \cdot ( j x + 1 )}

What is expand (-4v,-1,2u+1)(0,2,1) ?
The solution to expand (-4v,-1,2u+1)(0,2,1) is -4(0*2*1,,)v,-1*(0*2*1,,),2u+1*(0*2*1,,)