What is expand 1/((jx+4)*(jx+1)) ?

The solution to expand 1/((jx+4)*(jx+1)) is 1/(j^2x^2+5jx+4)

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expand 1/((jx+4)*(jx+1))

expand

\frac{1}{( j x + 4 ) \cdot ( j x + 1 )}

\frac{1}{j ^{2} x ^{2} + 5 j x + 4}

Solution steps

\frac{1}{( j x + 4 ) ( j x + 1 )}

Expand

(j x + 4) (j x + 1) : j^{2} x^{2} + 5 j x + 4

= \frac{1}{j ^{2} x ^{2} + 5 j x + 4}

\frac{\partial ^{2}}{\partial u \partial x} ((x) (- 2 x + u (x)))

\frac{( A s ) + B}{( s ^{2} + 1 ) ^{2}} + \frac{( C s ) + D}{s ^{2} + 1}

\frac{4 ( x + 1 )}{2 x + 1}

q (200 - 200 q - b q)^{2}

(100 - 2 π x)^{2}

What is expand 1/((jx+4)*(jx+1)) ?
The solution to expand 1/((jx+4)*(jx+1)) is 1/(j^2x^2+5jx+4)