What is expand s/((s^2+2)(s^4-2s-1)) ?

The solution to expand s/((s^2+2)(s^4-2s-1)) is s/(s^6-2s^3-s^2+2s^4-4s-2)

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expand s/((s^2+2)(s^4-2s-1))

expand

\frac{s}{( s ^{2} + 2 ) ( s ^{4} - 2 s - 1 )}

\frac{s}{s ^{6} - 2 s ^{3} - s ^{2} + 2 s ^{4} - 4 s - 2}

Solution steps

\frac{s}{( s ^{2} + 2 ) ( s ^{4} - 2 s - 1 )}

Expand

(s^{2} + 2) (s^{4} - 2 s - 1) : s^{6} - 2 s^{3} - s^{2} + 2 s^{4} - 4 s - 2

= \frac{s}{s ^{6} - 2 s ^{3} - s ^{2} + 2 s ^{4} - 4 s - 2}

(e^{x} + 1)^{15}

\frac{3 ( 8 - x ^{2} ) ^{2}}{2}

\frac{a ^{2} + ab}{( a - b ) ^{2}}

- \frac{4 ( - 4 s ^{2} + 1 )}{( 4 s ^{2} + 1 ) ^{2}}

0^{2} + \frac{x}{2} - (- \frac{x}{2} - 10 = 0)

What is expand s/((s^2+2)(s^4-2s-1)) ?
The solution to expand s/((s^2+2)(s^4-2s-1)) is s/(s^6-2s^3-s^2+2s^4-4s-2)