What is expand (3(8-x^2)^2)/2 ?

The solution to expand (3(8-x^2)^2)/2 is (3x^4)/2-24x^2+96

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expand (3(8-x^2)^2)/2

expand

\frac{3 ( 8 - x ^{2} ) ^{2}}{2}

\frac{3 x ^{4}}{2} - 24 x^{2} + 96

Solution steps

\frac{3 ( 8 - x ^{2} ) ^{2}}{2}

(8 - x^{2})^{2} = 64 - 16 x^{2} + x^{4}

= \frac{3 ( x ^{4} - 16 x ^{2} + 64 )}{2}

Expand

3 (64 - 16 x^{2} + x^{4}) : 192 - 48 x^{2} + 3 x^{4}

= \frac{192 - 48 x ^{2} + 3 x ^{4}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{192 - 48 x ^{2} + 3 x ^{4}}{2} = \frac{192}{2} - \frac{48 x ^{2}}{2} + \frac{3 x ^{4}}{2}

= \frac{192}{2} - \frac{48 x ^{2}}{2} + \frac{3 x ^{4}}{2}

Divide the numbers:

\frac{192}{2} = 96

= 96 - \frac{48 x ^{2}}{2} + \frac{3 x ^{4}}{2}

Divide the numbers:

\frac{48}{2} = 24

= 96 - 24 x^{2} + \frac{3 x ^{4}}{2}

Rewrite in standard form

= \frac{3 x ^{4}}{2} - 24 x^{2} + 96

\frac{a ^{2} + ab}{( a - b ) ^{2}}

- \frac{4 ( - 4 s ^{2} + 1 )}{( 4 s ^{2} + 1 ) ^{2}}

0^{2} + \frac{x}{2} - (- \frac{x}{2} - 10 = 0)

(9 x + 27) (9 y - 9)^{^{'}}

\frac{1}{( x - h ) ^{3}}

What is expand (3(8-x^2)^2)/2 ?
The solution to expand (3(8-x^2)^2)/2 is (3x^4)/2-24x^2+96