What is ((sqrt(63)+sqrt(112))*sqrt(28))/(42) ?

The solution to ((sqrt(63)+sqrt(112))*sqrt(28))/(42) is 7/3

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simplify ((sqrt(63)+sqrt(112))*sqrt(28))/(42)

simplify

\frac{( 63 + 112 ) \cdot 28}{42}

\frac{7}{3}

Decimal Notation

2.33333 \dots

Solution steps

\frac{( 63 + 112 ) 28}{42}

Factor

28 : 27

= \frac{( 63 + 112 ) \cdot 2 7}{42}

Factor the number:

42 = 2 \cdot 21

= \frac{( 63 + 112 ) \cdot 2 7}{2 \cdot 21}

Cancel the common factor:

2

= \frac{( 63 + 112 ) 7}{21}

Factor the number:

21 = 7 \cdot 3

= \frac{( 63 + 112 ) 7}{7 \cdot 3}

Apply radical rule:

a = a a

7 = 77

= \frac{( 63 + 112 ) 7}{7 7 \cdot 3}

Cancel the common factor:

7

= \frac{63 + 112}{7 \cdot 3}

\frac{63 + 112}{7 \cdot 3} = \frac{7}{3}

= \frac{7}{3}

\frac{30 x ^{8} y ^{4}}{18 x ^{3} y ^{2}}

\frac{3 x + 5}{2 - 5 x} \geq 2

\frac{4 2}{3 5}

- 5 x - 6 \geq 9

x^{2} + (10 - 2 x)^{2} = 25

What is ((sqrt(63)+sqrt(112))*sqrt(28))/(42) ?
The solution to ((sqrt(63)+sqrt(112))*sqrt(28))/(42) is 7/3