What is expand 1/(sqrt(9+6x)) ?

The solution to expand 1/(sqrt(9+6x)) is (sqrt(9+6x))/(9+6x)

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expand 1/(sqrt(9+6x))

expand

\frac{1}{9 + 6 x}

\frac{9 + 6 x}{9 + 6 x}

Solution steps

\frac{1}{9 + 6 x}

Multiply by the conjugate

\frac{9 + 6 x}{9 + 6 x}

= \frac{1 \cdot 9 + 6 x}{9 + 6 x 9 + 6 x}

1 \cdot 9 + 6 x = 9 + 6 x

9 + 6 x 9 + 6 x = 9 + 6 x

= \frac{9 + 6 x}{9 + 6 x}

1 + sin (b) (12, - 9)

\frac{( x - 3 ) \cdot ( 25 \cdot x - 75 )}{2}

\frac{1}{( t ^{2} - 9 ) ^{2}}

\frac{270000 \cdot 0.05}{1 - ( 1 - 9 ) ^{- 60}}

\frac{C ( 2 ^{X} + 3 ^{X} )}{6 ^{X}}

What is expand 1/(sqrt(9+6x)) ?
The solution to expand 1/(sqrt(9+6x)) is (sqrt(9+6x))/(9+6x)