What is expand 1+sin(b)(12,-9) ?

The solution to expand 1+sin(b)(12,-9) is 1+12sin(b),-9sin(b)

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expand 1+sin(b)(12,-9)

expand

1 + sin (b) (12, - 9)

1 + 12 sin (b), - 9 sin (b)

Solution steps

1 + sin (b) (12, - 9)

= 1 + (12, - 9) sin (b)

Expand

sin (b) (12, - 9) : 12 sin (b), - 9 sin (b)

= 1 + 12 sin (b), - 9 sin (b)

\frac{( x - 3 ) \cdot ( 25 \cdot x - 75 )}{2}

\frac{1}{( t ^{2} - 9 ) ^{2}}

\frac{270000 \cdot 0.05}{1 - ( 1 - 9 ) ^{- 60}}

\frac{C ( 2 ^{X} + 3 ^{X} )}{6 ^{X}}

x^{n + 1} (x^{n} + 3) + x^{n} (x^{3} - 1)^{'}

What is expand 1+sin(b)(12,-9) ?
The solution to expand 1+sin(b)(12,-9) is 1+12sin(b),-9sin(b)