What is expand (3(2*4^{1/3}-2^{1/3}))/2 ?

The solution to expand (3(2*4^{1/3}-2^{1/3}))/2 is 3*4^{1/3}-3/(2^{2/3)}

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expand (3(2*4^{1/3}-2^{1/3}))/2

expand

\frac{3 ( 2 \cdot 4 ^{\frac{1}{3}} - 2 ^{\frac{1}{3}} )}{2}

3 \cdot 4^{\frac{1}{3}} - \frac{3}{2 ^{\frac{2}{3}}}

Decimal Notation

2.87232 \dots

Solution steps

\frac{3 ( 2 \cdot 4 ^{\frac{1}{3}} - 2 ^{\frac{1}{3}} )}{2}

Expand

3 (2 \cdot 4^{\frac{1}{3}} - 2^{\frac{1}{3}}) : 6 \cdot 4^{\frac{1}{3}} - 3 \cdot 2^{\frac{1}{3}}

= \frac{6 \cdot 4 ^{\frac{1}{3}} - 3 \cdot 2 ^{\frac{1}{3}}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 \cdot 4 ^{\frac{1}{3}} - 3 \cdot 2 ^{\frac{1}{3}}}{2} = \frac{6 \cdot 4 ^{\frac{1}{3}}}{2} - \frac{3 \cdot 2 ^{\frac{1}{3}}}{2}

= \frac{6 \cdot 4 ^{\frac{1}{3}}}{2} - \frac{3 \cdot 2 ^{\frac{1}{3}}}{2}

Divide the numbers:

\frac{6}{2} = 3

= 3 \cdot 4^{\frac{1}{3}} - \frac{3 \cdot 2 ^{\frac{1}{3}}}{2}

Cancel

\frac{3 \cdot 2 ^{\frac{1}{3}}}{2} : \frac{3}{2 ^{\frac{2}{3}}}

= 3 \cdot 4^{\frac{1}{3}} - \frac{3}{2 ^{\frac{2}{3}}}

(t + 1) \cdot \frac{df}{d t}

(2 x - 3) (2 x^{2} = 3 x - 7)

1 - e^{- x} (1 + x)

\frac{15}{( 2 - x ) ^{2}}

\frac{\partial}{\partial x} ((x - 1)^{2}) + (y - 2)^{2}

What is expand (3(2*4^{1/3}-2^{1/3}))/2 ?
The solution to expand (3(2*4^{1/3}-2^{1/3}))/2 is 3*4^{1/3}-3/(2^{2/3)}