What are the solutions to the equation 5x^2-8x=4 ?

The solutions to the equation 5x^2-8x=4 are x=2,x=-2/5

Find the zeros of 5x^2-8x=4

The zeros of 5x^2-8x=4 are x=2,x=-2/5

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5 x^{2} - 8 x = 4

x = 2, x = - \frac{2}{5}

Decimal Notation

x = 2, x = - 0.4

Solution steps

5 x^{2} - 8 x = 4

Move

4

to the left side

5 x^{2} - 8 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

(- 8)^{2} - 4 \cdot 5 (- 4) = 12

x_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 5}, x_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 5}

x = \frac{- ( - 8 ) + 12}{2 \cdot 5} : 2

x = \frac{- ( - 8 ) - 12}{2 \cdot 5} : - \frac{2}{5}

The solutions to the quadratic equation are:

x = 2, x = - \frac{2}{5}

\frac{5 ^{10}}{5 ^{3}}

\frac{1}{14} (3 x - 2) = \frac{x + 10}{10}

x^{2} + 0.02 x + 0.04 = 0

\frac{1}{3} + \frac{2}{7} + \frac{8}{21}

x^{2} + 2 = 6 x

What are the solutions to the equation 5x^2-8x=4 ?
The solutions to the equation 5x^2-8x=4 are x=2,x=-2/5
Find the zeros of 5x^2-8x=4
The zeros of 5x^2-8x=4 are x=2,x=-2/5