What is expand pi/4 (rcos(θ^2)+rsin(θ^2)) ?

The solution to expand pi/4 (rcos(θ^2)+rsin(θ^2)) is (pircos(θ^2))/4+(pirsin(θ^2))/4

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expand pi/4 (rcos(θ^2)+rsin(θ^2))

expand

\frac{π}{4} (r cos (θ^{2}) + r sin (θ^{2}))

\frac{π r cos ( θ ^{2} )}{4} + \frac{π r sin ( θ ^{2} )}{4}

Solution steps

\frac{π}{4} (r cos (θ^{2}) + r sin (θ^{2}))

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{π}{4}, b = r cos (θ^{2}), c = r sin (θ^{2})

= \frac{π}{4} r cos (θ^{2}) + \frac{π}{4} r sin (θ^{2})

Simplify

\frac{π}{4} r cos (θ^{2}) + \frac{π}{4} r sin (θ^{2}) : \frac{π r cos ( θ ^{2} )}{4} + \frac{π r sin ( θ ^{2} )}{4}

= \frac{π r cos ( θ ^{2} )}{4} + \frac{π r sin ( θ ^{2} )}{4}

\frac{( 3 x - 1 ) ( x + 2 )}{x - 1}

\frac{9 w ^{2} + 9 w - 4}{3 w ^{2} + 7 w + 4}

\frac{x}{( x ^{2} - 5 ) ^{3}}

\frac{1}{0.2 i + \frac{3 i + 5}{30 i} + 1}

\frac{( 2 x + 3 ) e ^{- 2 x}}{x}

What is expand pi/4 (rcos(θ^2)+rsin(θ^2)) ?
The solution to expand pi/4 (rcos(θ^2)+rsin(θ^2)) is (pircos(θ^2))/4+(pirsin(θ^2))/4