What is expand ((x-2)(x+2))/((x+1)(x+3)) ?

The solution to expand ((x-2)(x+2))/((x+1)(x+3)) is (x^2-4)/(x^2+4x+3)

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expand ((x-2)(x+2))/((x+1)(x+3))

expand

\frac{( x - 2 ) ( x + 2 )}{( x + 1 ) ( x + 3 )}

\frac{x ^{2} - 4}{x ^{2} + 4 x + 3}

Solution steps

\frac{( x - 2 ) ( x + 2 )}{( x + 1 ) ( x + 3 )}

Expand

(x + 1) (x + 3) : x^{2} + 4 x + 3

= \frac{( x - 2 ) ( x + 2 )}{x ^{2} + 4 x + 3}

Expand

(x - 2) (x + 2) : x^{2} - 4

= \frac{x ^{2} - 4}{x ^{2} + 4 x + 3}

(m^{2} + n^{3})^{2} - 4 m^{2} y^{3}

\frac{d}{d x} ((z) (\frac{z}{z + 2} + 1))

- \frac{l k ( l sin ( \frac{2 π x}{l} ) + 2 C π )}{4 π ^{2}}

3 (y - 40 = - 38)

f (∣ x ∣ - 1) e^{∣ x ∣}

What is expand ((x-2)(x+2))/((x+1)(x+3)) ?
The solution to expand ((x-2)(x+2))/((x+1)(x+3)) is (x^2-4)/(x^2+4x+3)