What is expand 1/((4j^3+8j^2+3j)(5j+1)) ?

The solution to expand 1/((4j^3+8j^2+3j)(5j+1)) is 1/(20j^4+44j^3+23j^2+3j)

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expand 1/((4j^3+8j^2+3j)(5j+1))

expand

\frac{1}{( 4 j ^{3} + 8 j ^{2} + 3 j ) ( 5 j + 1 )}

\frac{1}{20 j ^{4} + 44 j ^{3} + 23 j ^{2} + 3 j}

Solution steps

\frac{1}{( 4 j ^{3} + 8 j ^{2} + 3 j ) ( 5 j + 1 )}

Expand

(4 j^{3} + 8 j^{2} + 3 j) (5 j + 1) : 20 j^{4} + 44 j^{3} + 23 j^{2} + 3 j

= \frac{1}{20 j ^{4} + 44 j ^{3} + 23 j ^{2} + 3 j}

\frac{100}{x ^{2} ( 2 + x ) ( 20 + x )}

\frac{4 x ^{2} ( 3 x + y ) ^{4}}{( 1 - x ) ^{2} ( 1 - x + y ) ^{2} ( x - y ) ^{2}}

- \frac{b ( 4 a ^{4} b - 3 )}{2 c ( 3 ab c + 2 )}

\frac{4 x}{( x ^{2} + 1 ) ( x ^{2} - 1 )}

csc (θ) (25, - 4)

What is expand 1/((4j^3+8j^2+3j)(5j+1)) ?
The solution to expand 1/((4j^3+8j^2+3j)(5j+1)) is 1/(20j^4+44j^3+23j^2+3j)