What is expand ((16x^2+1)^2)/(64x^2) ?

The solution to expand ((16x^2+1)^2)/(64x^2) is 4x^2+1/2+1/(64x^2)

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expand ((16x^2+1)^2)/(64x^2)

expand

\frac{( 16 x ^{2} + 1 ) ^{2}}{64 x ^{2}}

4 x^{2} + \frac{1}{2} + \frac{1}{64 x ^{2}}

Solution steps

\frac{( 16 x ^{2} + 1 ) ^{2}}{64 x ^{2}}

(16 x^{2} + 1)^{2} = 256 x^{4} + 32 x^{2} + 1

= \frac{256 x ^{4} + 32 x ^{2} + 1}{64 x ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{256 x ^{4} + 32 x ^{2} + 1}{64 x ^{2}} = \frac{256 x ^{4}}{64 x ^{2}} + \frac{32 x ^{2}}{64 x ^{2}} + \frac{1}{64 x ^{2}}

= \frac{256 x ^{4}}{64 x ^{2}} + \frac{32 x ^{2}}{64 x ^{2}} + \frac{1}{64 x ^{2}}

Cancel

\frac{256 x ^{4}}{64 x ^{2}} : 4 x^{2}

= 4 x^{2} + \frac{32 x ^{2}}{64 x ^{2}} + \frac{1}{64 x ^{2}}

Cancel

\frac{32 x ^{2}}{64 x ^{2}} : \frac{1}{2}

= 4 x^{2} + \frac{1}{2} + \frac{1}{64 x ^{2}}

\frac{x + 6}{( x + 2 ) \cdot ( x + 3 )}

\frac{( a - b c ) ^{2}}{4 n ^{2}}

(2 + 5 = 6,) v (5 - 3 = 4)

\frac{t ( x _{2} - x _{1} ) ( 2 + x _{1} + x _{2} )}{3}

\frac{3 ( 15 x - 3 )}{( x + 2 )}

What is expand ((16x^2+1)^2)/(64x^2) ?
The solution to expand ((16x^2+1)^2)/(64x^2) is 4x^2+1/2+1/(64x^2)