What is expand ,3(x+1)^3+(x+1)^2-2(x+1) ?

The solution to expand ,3(x+1)^3+(x+1)^2-2(x+1) is 3x^3+10x^2+9x+2

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expand ,3(x+1)^3+(x+1)^2-2(x+1)

expand

3 (x + 1)^{3} + (x + 1)^{2} - 2 (x + 1)

3 x^{3} + 10 x^{2} + 9 x + 2

Solution steps

3 (x + 1)^{3} + (x + 1)^{2} - 2 (x + 1)

Expand

3 (x + 1)^{3} : 3 x^{3} + 9 x^{2} + 9 x + 3

= 3 x^{3} + 9 x^{2} + 9 x + 3 + (x + 1)^{2} - 2 (x + 1)

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

= 3 x^{3} + 9 x^{2} + 9 x + 3 + x^{2} + 2 x + 1 - 2 (x + 1)

Expand

- 2 (x + 1) : - 2 x - 2

= 3 x^{3} + 9 x^{2} + 9 x + 3 + x^{2} + 2 x + 1 - 2 x - 2

Simplify

3 x^{3} + 9 x^{2} + 9 x + 3 + x^{2} + 2 x + 1 - 2 x - 2 : 3 x^{3} + 10 x^{2} + 9 x + 2

= 3 x^{3} + 10 x^{2} + 9 x + 2

\frac{( ( 2 x - 1 ) ^{3} ( 26 - 6 x ) )}{( 4 - x ) ^{3}}

\frac{d}{d x} ((x - 2) (x - 5)^{3}) + 5

(\frac{2 x - 1}{x + 1})^{2}

\frac{2 ( x + 6 )}{( x + 4 ) ( x - 4 )}

x (x^{2} + 3 x + 2)^{2}

What is expand ,3(x+1)^3+(x+1)^2-2(x+1) ?
The solution to expand ,3(x+1)^3+(x+1)^2-2(x+1) is 3x^3+10x^2+9x+2