What is expand pi(4(4x-(x^3)/6+(x^5)/(320))) ?

The solution to expand pi(4(4x-(x^3)/6+(x^5)/(320))) is (pix^5}{80}-\frac{2pix^3)/3+16pix

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expand pi(4(4x-(x^3)/6+(x^5)/(320)))

expand

π (4 (4 x - \frac{x ^{3}}{6} + \frac{x ^{5}}{320}))

\frac{π x ^{5}}{80} - \frac{2 π x ^{3}}{3} + 16 π x

Solution steps

π (4 (4 x - \frac{x ^{3}}{6} + \frac{x ^{5}}{320}))

Remove parentheses:

(a) = a

= π 4 (4 x - \frac{x ^{3}}{6} + \frac{x ^{5}}{320})

= 4 π (4 x - \frac{x ^{3}}{6} + \frac{x ^{5}}{320})

Distribute parentheses

= π 4 \cdot 4 x + π 4 (- \frac{x ^{3}}{6}) + π 4 \cdot \frac{x ^{5}}{320}

Apply minus-plus rules

+ (- a) = - a

= 4 \cdot 4 π x - 4 π \frac{x ^{3}}{6} + 4 π \frac{x ^{5}}{320}

Simplify

4 \cdot 4 π x - 4 π \frac{x ^{3}}{6} + 4 π \frac{x ^{5}}{320} : 16 π x - \frac{2 π x ^{3}}{3} + \frac{π x ^{5}}{80}

= 16 π x - \frac{2 π x ^{3}}{3} + \frac{π x ^{5}}{80}

Rewrite in standard form

= \frac{π x ^{5}}{80} - \frac{2 π x ^{3}}{3} + 16 π x

\frac{1}{( s ^{2} + 1 ) ( s - 1 )}

\frac{4 ( 6 + 786 )}{25}

sin (\frac{2}{3} (x + 2 π))

\frac{2 ( a ^{2} - b ^{2} )}{ab}

u^{2} + (6) u - (\frac{( - 7 ) ^{3}}{27})

What is expand pi(4(4x-(x^3)/6+(x^5)/(320))) ?
The solution to expand pi(4(4x-(x^3)/6+(x^5)/(320))) is (pix^5}{80}-\frac{2pix^3)/3+16pix