What is (d^2)/(dx^2)((y)(-4x+40)) ?

The answer to (d^2)/(dx^2)((y)(-4x+40)) is -4x(d^2y)/(dx^2)+40(d^2y)/(dx^2)-8(dy)/(dx)

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(d^2)/(dx^2)((y)(-4x+40))

\frac{d ^{2}}{d x ^{2}} ((y) (- 4 x + 40))

- 4 x \frac{d ^{2} y}{d x ^{2}} + 40 \frac{d ^{2} y}{d x ^{2}} - 8 \frac{d y}{d x}

Solution steps

\frac{d ^{2}}{d x ^{2}} ((y) (- 4 x + 40))

\frac{d}{d x} (y (- 4 x + 40)) = \frac{d y}{d x} (- 4 x + 40) - 4 y

= \frac{d}{d x} (\frac{d y}{d x} (- 4 x + 40) - 4 y)

\frac{d}{d x} (\frac{d y}{d x} (- 4 x + 40) - 4 y) = - 4 x \frac{d ^{2} y}{d x ^{2}} + 40 \frac{d ^{2} y}{d x ^{2}} - 8 \frac{d y}{d x}

= - 4 x \frac{d ^{2} y}{d x ^{2}} + 40 \frac{d ^{2} y}{d x ^{2}} - 8 \frac{d y}{d x}

x y^{''} (x) + 2 y^{'} (x) - \frac{2 x y}{( 1 - x ) ^{2}}

\frac{( ( s + 1 ) ^{3} )}{s ^{4}}

\frac{2 + s ^{2}}{s ( s ^{2} + 1 )}

0.2 - (x^{3} - (5 - x)^{3} \cdot 8900 = 0)

\frac{( 9 ( s + 5 ) )}{( ( s + 20 ) ( s + 15 ) )}

What is (d^2)/(dx^2)((y)(-4x+40)) ?
The answer to (d^2)/(dx^2)((y)(-4x+40)) is -4x(d^2y)/(dx^2)+40(d^2y)/(dx^2)-8(dy)/(dx)