What is expand 2(x^3-1)ln(x^3-1) ?

The solution to expand 2(x^3-1)ln(x^3-1) is 2x^3ln(x^3-1)-2ln(x^3-1)

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expand 2(x^3-1)ln(x^3-1)

expand

2 (x^{3} - 1) ln (x^{3} - 1)

2 x^{3} ln (x^{3} - 1) - 2 ln (x^{3} - 1)

Solution steps

2 (x^{3} - 1) ln (x^{3} - 1)

= 2 ln (x^{3} - 1) (x^{3} - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = 2 ln (x^{3} - 1), b = x^{3}, c = 1

= 2 ln (x^{3} - 1) x^{3} - 2 ln (x^{3} - 1) \cdot 1

= 2 x^{3} ln (x^{3} - 1) - 2 \cdot 1 \cdot ln (x^{3} - 1)

Multiply the numbers:

2 \cdot 1 = 2

= 2 x^{3} ln (x^{3} - 1) - 2 ln (x^{3} - 1)

x^{\frac{3}{2}} + x^{- \frac{1}{3}}

\frac{3 - 5 ( x + h ) ^{2} - 3 - 5 x ^{2}}{4 h}

\frac{2 z ( z ^{2} + 2 z - 8 )}{( z - 1 ) ( z + 2 )}

\frac{e ^{x}}{( 1 - e ^{x} ) ^{2} d x}

(8 x^{2} + 4 y) x^{2} + y^{2} = 1

What is expand 2(x^3-1)ln(x^3-1) ?
The solution to expand 2(x^3-1)ln(x^3-1) is 2x^3ln(x^3-1)-2ln(x^3-1)