What is expand (xz)/(xx)(yz+xln(y)=z^2) ?

The solution to expand (xz)/(xx)(yz+xln(y)=z^2) is (z^2y)/x+zln(y)=z^2

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expand (xz)/(xx)(yz+xln(y)=z^2)

expand

\frac{x z}{xx} (yz + x ln (y) = z^{2})

\frac{z ^{2} y}{x} + z ln (y) = z^{2}

Solution steps

\frac{x z}{xx} (yz + x ln (y) = z^{2})

= \frac{x z}{xx} (zy + = x z^{2} ln (y))

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{x z}{xx}, b = yz, c = x ln (y) = z^{2}

\frac{x z}{xx} yz + \frac{x z}{xx} x ln (y) = z^{2}

\frac{x z}{xx} zy + \frac{x z}{xx} x ln (y) = z^{2}

Expand

\frac{x z}{xx} zy + \frac{x z}{xx} x ln (y) : \frac{z ^{2} y}{x} + z ln (y)

\frac{z ^{2} y}{x} + z ln (y) = z^{2}

\frac{- 2 x ^{2} + 8}{( x ^{2} + 4 ) ^{2}}

\frac{i}{8} \cdot (cos (2 π x) + i sin (2 π x))^{3}

\frac{( n + 1 ) ( n + 3 ) ( 2 n + 9 )}{6}

\frac{4 x ^{2}}{( 2 x ^{3} - 11 ) ^{\frac{1}{3}} \cdot ( 2 x - 1 )}

\frac{1}{z ( 1 - z ) ^{3}}

What is expand (xz)/(xx)(yz+xln(y)=z^2) ?
The solution to expand (xz)/(xx)(yz+xln(y)=z^2) is (z^2y)/x+zln(y)=z^2