What are the solutions to the equation 6a^2-2a=7 ?

The solutions to the equation 6a^2-2a=7 are a=(1+sqrt(43))/6 ,a=(1-sqrt(43))/6

Find the zeros of 6a^2-2a=7

The zeros of 6a^2-2a=7 are a=(1+sqrt(43))/6 ,a=(1-sqrt(43))/6

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6 a^{2} - 2 a = 7

a = \frac{1 + 43}{6}, a = \frac{1 - 43}{6}

Decimal Notation

a = 1.25957 \dots, a = - 0.92623 \dots

Solution steps

6 a^{2} - 2 a = 7

Move

7

to the left side

6 a^{2} - 2 a - 7 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 6 ( - 7 )}{2 \cdot 6}

(- 2)^{2} - 4 \cdot 6 (- 7) = 243

a_{1, 2} = \frac{- ( - 2 ) \pm 2 43}{2 \cdot 6}

Separate the solutions

a_{1} = \frac{- ( - 2 ) + 2 43}{2 \cdot 6}, a_{2} = \frac{- ( - 2 ) - 2 43}{2 \cdot 6}

a = \frac{- ( - 2 ) + 2 43}{2 \cdot 6} : \frac{1 + 43}{6}

a = \frac{- ( - 2 ) - 2 43}{2 \cdot 6} : \frac{1 - 43}{6}

The solutions to the quadratic equation are:

a = \frac{1 + 43}{6}, a = \frac{1 - 43}{6}

25 = 4 x^{2} - 5 x - 50

1 = \frac{1}{3} (4 v + 3)

6 - \frac{1}{6} x = \frac{16}{3}

5 x - \frac{2}{5} \leq 2 - \frac{7 x}{2} < 3

What are the solutions to the equation 6a^2-2a=7 ?
The solutions to the equation 6a^2-2a=7 are a=(1+sqrt(43))/6 ,a=(1-sqrt(43))/6
Find the zeros of 6a^2-2a=7
The zeros of 6a^2-2a=7 are a=(1+sqrt(43))/6 ,a=(1-sqrt(43))/6