en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify e^{-ln(x^2-1)}

Solution

simplify

e^{- l n (x^{2} - 1)}

Solution

\frac{1}{x ^{2} - 1}

Solution steps

e^{- l n (x^{2} - 1)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n (x^{2} - 1)}}

e^{l n (x^{2} - 1)} = x^{2} - 1

= \frac{1}{x ^{2} - 1}

Popular Examples

simplify e^{-ln(4/5)= 5/25}simplify

e^{- l n (\frac{4}{5}) = \frac{5}{25}}

simplify 3ac^3f^3 simplify

3 a c^{3} f^{3}

simplify 3.33*(6.66*10^{-4})simplify

3.33 \cdot (6.66 \cdot 1 0^{- 4})

simplify e^{-(3/4)pi}simplify

e^{- (\frac{3}{4}) π}

simplify \sqrt[3]{3328}^2\sqrt[3]{416}pi simplify

Frequently Asked Questions (FAQ)

What is e^{-ln(x^2-1)} ?
The solution to e^{-ln(x^2-1)} is 1/(x^2-1)