What are the solutions to the equation a^2+14^2=28^2 ?

The solutions to the equation a^2+14^2=28^2 are a=14sqrt(3),a=-14sqrt(3)

Find the zeros of a^2+14^2=28^2

The zeros of a^2+14^2=28^2 are a=14sqrt(3),a=-14sqrt(3)

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a^{2} + 1 4^{2} = 2 8^{2}

a = 143, a = - 143

Decimal Notation

a = 24.24871 \dots, a = - 24.24871 \dots

Solution steps

a^{2} + 1 4^{2} = 2 8^{2}

Move

1 4^{2}

to the right side

a^{2} = 588

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 588, a = - 588

588 = 143

- 588 = - 143

a = 143, a = - 143

3 a^{2} - 36 = 81

7 x + 1 = 9 x - 7

\frac{h ^{4}}{h ^{6}}

2 x^{2} - 13 x + 6 = 0

\frac{9 - x ^{2}}{x ^{2} - x - 2} \geq 0

What are the solutions to the equation a^2+14^2=28^2 ?
The solutions to the equation a^2+14^2=28^2 are a=14sqrt(3),a=-14sqrt(3)
Find the zeros of a^2+14^2=28^2
The zeros of a^2+14^2=28^2 are a=14sqrt(3),a=-14sqrt(3)