What are the solutions to the equation x^2+0^2-14x+4(0)+28=0 ?

The solutions to the equation x^2+0^2-14x+4(0)+28=0 are x=7+sqrt(21),x=7-sqrt(21)

Find the zeros of x^2+0^2-14x+4(0)+28=0

The zeros of x^2+0^2-14x+4(0)+28=0 are x=7+sqrt(21),x=7-sqrt(21)

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x^{2} + 0^{2} - 14 x + 4 (0) + 28 = 0

x = 7 + 21, x = 7 - 21

Solution steps

x^{2} + 0^{2} - 14 x + 4 (0) + 28 = 0

Expand

x^{2} + 0^{2} - 14 x + 4 (0) + 28 : x^{2} - 14 x + 28

x^{2} - 14 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 28 = 221

x_{1, 2} = \frac{- ( - 14 ) \pm 2 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 21}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 21}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 21}{2 \cdot 1} : 7 + 21

x = \frac{- ( - 14 ) - 2 21}{2 \cdot 1} : 7 - 21

The solutions to the quadratic equation are:

x = 7 + 21, x = 7 - 21

2 x^{2} + x - 21 = 0

m^{6} - 64

- 4 x + 12 \geq 20

(m - n)^{2} - 16

\frac{8}{7} ∣ x ∣ = 3

What are the solutions to the equation x^2+0^2-14x+4(0)+28=0 ?
The solutions to the equation x^2+0^2-14x+4(0)+28=0 are x=7+sqrt(21),x=7-sqrt(21)
Find the zeros of x^2+0^2-14x+4(0)+28=0
The zeros of x^2+0^2-14x+4(0)+28=0 are x=7+sqrt(21),x=7-sqrt(21)