What is 4^{sin(2x)}4ln(2)cos(2x) ?

The solution to 4^{sin(2x)}4ln(2)cos(2x) is ln(2)*4^{sin(2x)+1}cos(2x)

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simplify 4^{sin(2x)}4ln(2)cos(2x)

simplify

4^{s i n (2 x)} 4 ln (2) cos (2 x)

ln (2) \cdot 4^{s i n (2 x) + 1} cos (2 x)

Solution steps

4^{s i n (2 x)} \cdot 4 ln (2) cos (2 x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

4^{s i n (2 x)} \cdot 4 = 4^{s i n (2 x) + 1}

= 4^{s i n (2 x) + 1} ln (2) cos (2 x)

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(\frac{e ^{- 5 x} + e ^{y} - 1}{5})^{- 1}

\frac{d ^{2}}{d x ^{2}} ((y) (x e^{- x}))

2 e^{- \frac{1}{2}} (2 s + 3)

9500 \cdot e^{(- 0.55 t) = \frac{13}{7}}

What is 4^{sin(2x)}4ln(2)cos(2x) ?
The solution to 4^{sin(2x)}4ln(2)cos(2x) is ln(2)*4^{sin(2x)+1}cos(2x)