What are the solutions to the equation 3x^2(2x^2+3)=0 ?

The solutions to the equation 3x^2(2x^2+3)=0 are x=0,x=sqrt(3/2)i,x=-sqrt(3/2)i

Find the zeros of 3x^2(2x^2+3)=0

The zeros of 3x^2(2x^2+3)=0 are x=0,x=sqrt(3/2)i,x=-sqrt(3/2)i

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3 x^{2} (2 x^{2} + 3) = 0

x = 0, x = \frac{3}{2} i, x = - \frac{3}{2} i

Solution steps

3 x^{2} (2 x^{2} + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x^{2} + 3 = 0

Solve

2 x^{2} + 3 = 0 : x = \frac{3}{2} i, x = - \frac{3}{2} i

The solutions are

x = 0, x = \frac{3}{2} i, x = - \frac{3}{2} i

(10 x + 3)^{2} = 3

\frac{( x - 5 )}{x + 2} \geq - 6

(5 - 7)^{2}

\frac{x - 2}{8 x + 1} < 0

\frac{a - 2}{3} > a + 4

What are the solutions to the equation 3x^2(2x^2+3)=0 ?
The solutions to the equation 3x^2(2x^2+3)=0 are x=0,x=sqrt(3/2)i,x=-sqrt(3/2)i
Find the zeros of 3x^2(2x^2+3)=0
The zeros of 3x^2(2x^2+3)=0 are x=0,x=sqrt(3/2)i,x=-sqrt(3/2)i