What are the solutions to the equation (2y-1)^2=0 ?

The solutions to the equation (2y-1)^2=0 are y= 1/2

Find the zeros of (2y-1)^2=0

The zeros of (2y-1)^2=0 are y= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 y - 1)^{2} = 0

y = \frac{1}{2}

Solution steps

(2 y - 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

2 y - 1 = 0 : y = \frac{1}{2}

The solution to the quadratic equation is:

y = \frac{1}{2}

4 x^{2} + 100 = 0

\frac{5 \cdot 180}{3}

2 x - \frac{3}{2} = x

∣ 2 x ∣ < 1

\frac{( 2 n + 2 ) !}{( 2 n ) !}

What are the solutions to the equation (2y-1)^2=0 ?
The solutions to the equation (2y-1)^2=0 are y= 1/2
Find the zeros of (2y-1)^2=0
The zeros of (2y-1)^2=0 are y= 1/2