What is \sqrt[n]{a^x}*\sqrt[n]{a^{2x}} ?

The solution to \sqrt[n]{a^x}*\sqrt[n]{a^{2x}} is (a^{3x})^{1/n}

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simplify \sqrt[n]{a^x}*\sqrt[n]{a^{2x}}

simplify

(a^{3 x})^{\frac{1}{n}}

Solution steps

Apply radical rule:

assuming

a \geq 0, b \geq 0

= (a^{x} a^{2 x})^{\frac{1}{n}}

Simplify

a^{x} a^{2 x} : a^{3 x}

= (a^{3 x})^{\frac{1}{n}}

(2 X^{3}) (5 X^{3})

3 x^{2} y^{2} (- 3 x^{3} + 2 x^{2} y + 4 y^{5})

h (x^{2} (x + h)^{2})

e^{- 1.6} \cdot (\frac{1. 6 ^{4}}{4 !})

2^{7} \cdot 3^{7}

What is \sqrt[n]{a^x}*\sqrt[n]{a^{2x}} ?
The solution to \sqrt[n]{a^x}*\sqrt[n]{a^{2x}} is (a^{3x})^{1/n}