What is e^{-3t}sin(2t)cos(3t)cosh(t) ?

The solution to e^{-3t}sin(2t)cos(3t)cosh(t) is (sin(2t)cos(3t)cosh(t))/(e^{3t)}

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simplify e^{-3t}sin(2t)cos(3t)cosh(t)

simplify

e^{- 3 t} sin (2 t) cos (3 t) cosh (t)

\frac{sin ( 2 t ) cos ( 3 t ) cosh ( t )}{e ^{3 t}}

Solution steps

e^{- 3 t} sin (2 t) cos (3 t) cosh (t)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{3 t}} sin (2 t) cos (3 t) cosh (t)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot sin ( 2 t ) cos ( 3 t ) cosh ( t )}{e ^{3 t}}

Multiply:

1 \cdot sin (2 t) = sin (2 t)

= \frac{sin ( 2 t ) cos ( 3 t ) cosh ( t )}{e ^{3 t}}

(2 a^{3} b^{2}) (3 a^{4} b^{3})

2 \cdot 1 \cdot 1 0^{- 7} (\frac{2 \cdot 0.65}{0.25})

15000 e^{- 6286 (5)}

d^{- 1} x cos (x) d x

What is e^{-3t}sin(2t)cos(3t)cosh(t) ?
The solution to e^{-3t}sin(2t)cos(3t)cosh(t) is (sin(2t)cos(3t)cosh(t))/(e^{3t)}