What is (sqrt(t^4+4t^2+1))/(sqrt(1+t^6+t^{12))} ?

The solution to (sqrt(t^4+4t^2+1))/(sqrt(1+t^6+t^{12))} is sqrt((t^4+4t^2+1)/(t^{12)+t^6+1)}

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simplify (sqrt(t^4+4t^2+1))/(sqrt(1+t^6+t^{12))}

simplify

\frac{t ^{4} + 4 t ^{2} + 1}{1 + t ^{6} + t ^{12}}

\frac{t ^{4} + 4 t ^{2} + 1}{t ^{12} + t ^{6} + 1}

Solution steps

\frac{t ^{4} + 4 t ^{2} + 1}{1 + t ^{6} + t ^{12}}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}

\frac{t ^{4} + 4 t ^{2} + 1}{1 + t ^{6} + t ^{12}} = \frac{t ^{4} + 4 t ^{2} + 1}{1 + t ^{6} + t ^{12}}

= \frac{t ^{4} + 4 t ^{2} + 1}{1 + t ^{6} + t ^{12}}

e^{- 2 (t - t_{0})} u (t - 2 t_{0})

2.9 \cdot 1 0^{- 4} \cdot 58.3 3^{\frac{4}{3}}

What is (sqrt(t^4+4t^2+1))/(sqrt(1+t^6+t^{12))} ?
The solution to (sqrt(t^4+4t^2+1))/(sqrt(1+t^6+t^{12))} is sqrt((t^4+4t^2+1)/(t^{12)+t^6+1)}