What are the solutions to the equation 1=x^2+2x*0.2+0.04 ?

The solutions to the equation 1=x^2+2x*0.2+0.04 are x= 4/5 ,x=-6/5

Find the zeros of 1=x^2+2x*0.2+0.04

The zeros of 1=x^2+2x*0.2+0.04 are x= 4/5 ,x=-6/5

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1 = x^{2} + 2 x \cdot 0.2 + 0.04

x = \frac{4}{5}, x = - \frac{6}{5}

Decimal Notation

x = 0.8, x = - 1.2

Solution steps

1 = x^{2} + 2 x \cdot 0.2 + 0.04

Multiply both sides by

100

100 = 100 x^{2} + 40 x + 4

Switch sides

100 x^{2} + 40 x + 4 = 100

Move

100

to the left side

100 x^{2} + 40 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 100 ( - 96 )}{2 \cdot 100}

4 0^{2} - 4 \cdot 100 (- 96) = 200

x_{1, 2} = \frac{- 40 \pm 200}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- 40 + 200}{2 \cdot 100}, x_{2} = \frac{- 40 - 200}{2 \cdot 100}

x = \frac{- 40 + 200}{2 \cdot 100} : \frac{4}{5}

x = \frac{- 40 - 200}{2 \cdot 100} : - \frac{6}{5}

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = - \frac{6}{5}

(4 x + 1) (x - 8) = 0

\frac{5 !}{2 ! ( 5 - 2 ) !}

\frac{16 a ^{4} - 40 a ^{2} + 24 a}{12 a ^{3}}

328 = 8 (5 - 6 x)

3 \cdot 4

What are the solutions to the equation 1=x^2+2x*0.2+0.04 ?
The solutions to the equation 1=x^2+2x*0.2+0.04 are x= 4/5 ,x=-6/5
Find the zeros of 1=x^2+2x*0.2+0.04
The zeros of 1=x^2+2x*0.2+0.04 are x= 4/5 ,x=-6/5