What is e^{-4t}cos(h)(2t) ?

The solution to e^{-4t}cos(h)(2t) is (2tcos(h))/(e^{4t)}

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simplify e^{-4t}cos(h)(2t)

simplify

e^{- 4 t} cos (h) (2 t)

\frac{2 t cos ( h )}{e ^{4 t}}

Solution steps

e^{- 4 t} cos (h) (2 t)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 2 \cdot \frac{1}{e ^{4 t}} t cos (h)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot cos ( h ) \cdot 2 t}{e ^{4 t}}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{2 t cos ( h )}{e ^{4 t}}

25 - x^{2} x + 1

x^{- 4^{^{'}}}

25 - x^{2} x + 3

d x \frac{( 2 x + 1 ) ^{4}}{( 3 x - 1 ) ^{4}}

What is e^{-4t}cos(h)(2t) ?
The solution to e^{-4t}cos(h)(2t) is (2tcos(h))/(e^{4t)}