What are the solutions to the equation u^2-2u-8=0 ?

The solutions to the equation u^2-2u-8=0 are u=4,u=-2

Find the zeros of u^2-2u-8=0

The zeros of u^2-2u-8=0 are u=4,u=-2

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u^{2} - 2 u - 8 = 0

u = 4, u = - 2

Solution steps

u^{2} - 2 u - 8 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 8) = 6

u_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 1}, u_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 1}

u = \frac{- ( - 2 ) + 6}{2 \cdot 1} : 4

u = \frac{- ( - 2 ) - 6}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

u = 4, u = - 2

\frac{2}{3} - x \leq 2 + 5 x < 8 x + 6

\frac{1 + 2 i}{2 - i}

z^{2} + 2 z + 5 = 0

(7 x^{2}) (x^{3})

5 + 3^{- 2}

What are the solutions to the equation u^2-2u-8=0 ?
The solutions to the equation u^2-2u-8=0 are u=4,u=-2
Find the zeros of u^2-2u-8=0
The zeros of u^2-2u-8=0 are u=4,u=-2