What is (f\circ g)^{-1}(2) ?

The solution to (f\circ g)^{-1}(2) is 2/(\circ fg)

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simplify (f\circ g)^{-1}(2)

simplify

(f \circ g)^{- 1} (2)

\frac{2}{\circ f g}

Solution steps

(f \circ g)^{- 1} (2)

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= 2 \cdot \frac{1}{\circ f g}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{f \circ g}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{2}{\circ f g}

(12 x^{3} y^{2}) 23 x^{2} y

0.08 (1000) \cdot (1 + 0.0001 \cdot 1000)^{- \frac{1}{2}}

- x^{2} \cdot y^{2}

(8.987 \cdot 1 0^{9}) (8 \cdot 1 0^{- 12})

- 2 (x^{2} - 9) (2 x)