What is (50^{t^2-1/2 t})/(5^{t^2-1/2 t)} ?

The solution to (50^{t^2-1/2 t})/(5^{t^2-1/2 t)} is 10^{t^2-t/2}

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simplify (50^{t^2-1/2 t})/(5^{t^2-1/2 t)}

simplify

\frac{5 0 ^{t^{2} - \frac{1}{2} t}}{5 ^{t^{2} - \frac{1}{2} t}}

1 0^{t^{2} - \frac{t}{2}}

Solution steps

\frac{5 0 ^{t^{2} - \frac{1}{2} t}}{5 ^{t^{2} - \frac{1}{2} t}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{5 0 ^{t^{2} - \frac{1}{2} t}}{5 ^{t^{2} - \frac{1}{2} t}} = (\frac{50}{5})^{t^{2} - \frac{1}{2} t}

= (\frac{50}{5})^{t^{2} - \frac{1}{2} t}

Divide the numbers:

\frac{50}{5} = 10

= 1 0^{t^{2} - \frac{1}{2} t}

\frac{1}{2} t = \frac{t}{2}

= 1 0^{t^{2} - \frac{t}{2}}

(e^{\frac{- 1}{x ^{2}}})^{^{'}}

\frac{1}{2 π} e^{- \frac{2 ^{2}}{2}}

(0.018) \cdot (4.68 \cdot 1 0^{- 6})

(\frac{h}{2 π})^{2} \cdot π^{2}

What is (50^{t^2-1/2 t})/(5^{t^2-1/2 t)} ?
The solution to (50^{t^2-1/2 t})/(5^{t^2-1/2 t)} is 10^{t^2-t/2}