What is (e^x+e^{-x})*(e^x+e^{-x}) ?

The solution to (e^x+e^{-x})*(e^x+e^{-x}) is (e^x+e^{-x})^2

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simplify (e^x+e^{-x})*(e^x+e^{-x})

simplify

(e^{x} + e^{- x}) \cdot (e^{x} + e^{- x})

(e^{x} + e^{- x})^{2}

Solution steps

(e^{x} + e^{- x}) (e^{x} + e^{- x})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(e^{x} + e^{- x}) (e^{x} + e^{- x}) = (e^{x} + e^{- x})^{1 + 1}

= (e^{x} + e^{- x})^{1 + 1}

Add the numbers:

1 + 1 = 2

= (e^{x} + e^{- x})^{2}

4 - t \cdot t

- ln (1 - \frac{4.5}{5}) \cdot 266 \cdot 1 0^{- 12} \cdot 270

(4 \cdot 1 0^{a}) \cdot (3 \cdot 1 0^{b})

200 (1.1)^{t} \cdot 5000 (1.111)^{t}

\frac{1}{2} \cdot \frac{1}{2} (16 - x^{2})^{- \frac{1}{2}} \cdot (2 x)

What is (e^x+e^{-x})*(e^x+e^{-x}) ?
The solution to (e^x+e^{-x})*(e^x+e^{-x}) is (e^x+e^{-x})^2