What is (f\circ f^{-1})(10) ?

The solution to (f\circ f^{-1})(10) is 10\circ

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simplify (f\circ f^{-1})(10)

simplify

(f \circ f^{- 1}) (10)

10 \circ

Decimal Notation

10

Solution steps

(f \circ f^{- 1}) (10)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

f f^{- 1} = f^{1 - 1}

= \circ f^{1 - 1} \cdot 10

Subtract the numbers:

1 - 1 = 0

= \circ f^{0} \cdot 10

Apply rule

a^{0} = 1, a \neq = 0

f^{0} = 1

= 1 \cdot 10 \circ

Multiply the numbers:

1 \cdot 10 = 10

= 10 \circ

4 - x \cdot x^{2} - 9

e^{- \frac{28}{10}}

5 (hk)^{3}

e^{- 2 t} cos (π \cdot t \cdot u (t - 1))

e^{- 0.1 (10)}