What are the solutions to the equation -x^2+15x=73-3x ?

The solutions to the equation -x^2+15x=73-3x are x=9-2sqrt(2),x=9+2sqrt(2)

Find the zeros of -x^2+15x=73-3x

The zeros of -x^2+15x=73-3x are x=9-2sqrt(2),x=9+2sqrt(2)

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- x^{2} + 15 x = 73 - 3 x

x = 9 - 22, x = 9 + 22

Solution steps

- x^{2} + 15 x = 73 - 3 x

Move

3 x

to the left side

- x^{2} + 18 x = 73

Move

73

to the left side

- x^{2} + 18 x - 73 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 1 ) ( - 73 )}{2 ( - 1 )}

1 8^{2} - 4 (- 1) (- 73) = 42

x_{1, 2} = \frac{- 18 \pm 4 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 18 + 4 2}{2 ( - 1 )}, x_{2} = \frac{- 18 - 4 2}{2 ( - 1 )}

x = \frac{- 18 + 4 2}{2 ( - 1 )} : 9 - 22

x = \frac{- 18 - 4 2}{2 ( - 1 )} : 9 + 22

The solutions to the quadratic equation are:

x = 9 - 22, x = 9 + 22

3 \cdot \frac{2 π}{3}

\frac{1}{5} - \frac{1}{6}

\frac{x ^{2} + 1}{2} < 3

5 + 3 x = 2 (x + 3)

12 x^{2} + 25 x + 2

What are the solutions to the equation -x^2+15x=73-3x ?
The solutions to the equation -x^2+15x=73-3x are x=9-2sqrt(2),x=9+2sqrt(2)
Find the zeros of -x^2+15x=73-3x
The zeros of -x^2+15x=73-3x are x=9-2sqrt(2),x=9+2sqrt(2)