What is 2*k*(sqrt((20/3)^2+4.2096^2))^2 ?

The solution to 2*k*(sqrt((20/3)^2+4.2096^2))^2 is (437098898k)/(3515625)

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simplify 2k(sqrt((20/3)^2+4.2096^2))^2

simplify

2 \cdot k \cdot (\frac{20}{3})^{2} + 4.209 6^{2}^{2}

\frac{437098898 k}{3515625}

Solution steps

2 k (\frac{20}{3})^{2} + 4.209 6^{2}^{2}

(\frac{20}{3})^{2} + 4.209 6^{2}^{2} = \frac{218549449}{3515625}

= 2 k \frac{218549449}{3515625}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 k \cdot 218549449}{3515625}

Multiply the numbers:

2 \cdot 218549449 = 437098898

= \frac{437098898 k}{3515625}

2.14 \cdot 144 \cdot 1 0^{- 6} \cdot 120

e^{- f r a c^{12} (x^{2} + y^{2})}

1013 e^{- (- \frac{l n ( 0.88 )}{1000}) (9000)}

3.74 \cdot 1 0^{- 1}

2 π \cdot \frac{50}{π} \cdot 50 \cdot 1 0^{- 3}

What is 2*k*(sqrt((20/3)^2+4.2096^2))^2 ?
The solution to 2*k*(sqrt((20/3)^2+4.2096^2))^2 is (437098898k)/(3515625)