What is (8.99*10^{-9})(1*10^{-6})(1*10^{-6}) ?

The solution to (8.99*10^{-9})(1*10^{-6})(1*10^{-6}) is (899)/(100000000000*10^{12)}

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simplify (8.9910^{-9})(110^{-6})(1*10^{-6})

simplify

(8.99 \cdot 1 0^{- 9}) (1 \cdot 1 0^{- 6}) (1 \cdot 1 0^{- 6})

\frac{899}{100000000000 \cdot 1 0 ^{12}}

Solution steps

(8.99 \cdot 1 0^{- 9}) (1 \cdot 1 0^{- 6}) (1 \cdot 1 0^{- 6})

Apply exponent rule:

aa = a^{2}

(1 \cdot 1 0^{- 6}) (1 \cdot 1 0^{- 6}) = (1 \cdot 1 0^{- 6})^{2}

= 8.99 \cdot 1 0^{- 9} (1 \cdot 1 0^{- 6})^{2}

= 1 0^{- 9} \cdot 8.99 (1 \cdot 1 0^{- 6})^{2}

1 0^{- 9} = \frac{1}{1000000000}

= \frac{1}{1000000000} \cdot 8.99 (1 \cdot 1 0^{- 6})^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(1 \cdot 1 0^{- 6})^{2} = 1^{2} (1 0^{- 6})^{2}

= \frac{1}{1000000000} \cdot 8.99 \cdot 1^{2} (1 0^{- 6})^{2}

1^{2} = 1

= \frac{1}{1000000000} \cdot 8.99 \cdot 1 \cdot (1 0^{- 6})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}, a \geq 0

(1 0^{- 6})^{2} = 1 0^{- 6 \cdot 2}

= \frac{1}{1000000000} \cdot 8.99 \cdot 1 \cdot 1 0^{- 6 \cdot 2}

Multiply the numbers:

6 \cdot 2 = 12

= \frac{1}{1000000000} \cdot 8.99 \cdot 1 \cdot 1 0^{- 12}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 12} = \frac{1}{1 0 ^{12}}

= \frac{1}{1000000000} \cdot 8.99 \cdot 1 \cdot \frac{1}{1 0 ^{12}}

Multiply:

1 \cdot \frac{1}{1 0 ^{12}} = \frac{1}{1 0 ^{12}}

= \frac{1}{1000000000} \cdot 8.99 \cdot \frac{1}{1 0 ^{12}}

\frac{1}{1000000000} \cdot 8.99 \cdot \frac{1}{1 0 ^{12}} = \frac{8.99}{1 0 ^{12} \cdot 1000000000}

= \frac{8.99}{1 0 ^{12} \cdot 1000000000}

\frac{8.99}{1 0 ^{12} \cdot 1000000000} = \frac{899}{100000000000 \cdot 1 0 ^{12}}

= \frac{899}{100000000000 \cdot 1 0 ^{12}}

\frac{1}{2} π x^{2} \cdot x

(\frac{12}{10000}) \cdot 2.7 2^{- (\frac{35}{22})}

2000 e^{- \frac{24}{5}}

e^{- 0.12 (\frac{3}{12})} \cdot ((1 - 0.65227) \cdot 9.6)

(y \cdot x) (y^{2} \cdot x^{2})

What is (8.99*10^{-9})(1*10^{-6})(1*10^{-6}) ?
The solution to (8.99*10^{-9})(1*10^{-6})(1*10^{-6}) is (899)/(100000000000*10^{12)}