What is 1*((7)^{-0.3})*0.4 ?

The solution to 1*((7)^{-0.3})*0.4 is 2/(5*7^{0.3)}

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simplify 1((7)^{-0.3})0.4

simplify

1 \cdot ((7)^{- 0.3}) \cdot 0.4

\frac{2}{5 \cdot 7 ^{0.3}}

Decimal Notation

0.22311 \dots

Solution steps

1 \cdot (7^{- 0.3}) \cdot 0.4

Apply rule:

(a) = a

(7^{- 0.3}) = 7^{- 0.3}

= 1 \cdot 7^{- 0.3} \cdot 0.4

Multiply the numbers:

1 \cdot 0.4 = 0.4

= 0.4 \cdot 7^{- 0.3}

= 7^{- 0.3} \cdot 0.4

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

7^{- 0.3} = \frac{1}{7 ^{0.3}}

= \frac{1}{7 ^{0.3}} \cdot 0.4

\frac{1}{7 ^{0.3}} \cdot 0.4 = \frac{0.4}{7 ^{0.3}}

= \frac{0.4}{7 ^{0.3}}

\frac{0.4}{7 ^{0.3}} = \frac{4}{10 \cdot 7 ^{0.3}}

= \frac{4}{10 \cdot 7 ^{0.3}}

Factor the number:

4 = 2 \cdot 2

= \frac{2 \cdot 2}{10 \cdot 7 ^{0.3}}

Factor the number:

10 = 2 \cdot 5

= \frac{2 \cdot 2}{2 \cdot 5 \cdot 7 ^{0.3}}

Cancel the common factor:

2

= \frac{2}{5 \cdot 7 ^{0.3}}

(6.63 \cdot 1 0^{- 34}) (4.49 \cdot 1 0^{14})

2.15 \cdot 1 0^{- 2} \cdot 1.2 \cdot 125

e^{- t} sin^{2 t} (x)

f^{- 1} \circ f

(698 \cdot 1 0^{3}) \cdot (1.6 \cdot 1 0^{- 19})

What is 1*((7)^{-0.3})*0.4 ?
The solution to 1*((7)^{-0.3})*0.4 is 2/(5*7^{0.3)}