What is e^{-1/2 (1/2)^2 1/2} ?

The solution to e^{-1/2 (1/2)^2 1/2} is 1/(\sqrt[16]{e)}

Popular >

simplify e^{-1/2 (1/2)^2 1/2}

simplify

e^{- \frac{1}{2} (\frac{1}{2})^{2} \frac{1}{2}}

Decimal Notation

0.93941 \dots

Solution steps

e^{- \frac{1}{2} (\frac{1}{2})^{2} \frac{1}{2}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{(\frac{1}{2})^{2} \frac{1}{2} \cdot \frac{1}{2}}}

e^{\frac{1}{2} (\frac{1}{2})^{2} \frac{1}{2}} = e^{(\frac{1}{2})^{4}}

= \frac{1}{e ^{(\frac{1}{2})^{4}}}

e^{(\frac{1}{2})^{4}} = e^{\frac{1}{2 ^{4}}}

= \frac{1}{e ^{\frac{1}{2 ^{4}}}}

2^{4} = 16

x^{2} y^{2} (y^{4} - 5 x^{2})

1.72 \cdot 1 0^{- 3}

3 e^{- e (3)} (3^{2} - 16) (3^{2} + 1) (3 - 1)^{4}

\frac{\frac{16}{2}}{π \cdot ( \frac{0.013}{2} ) ^{2}} \cdot 1 0^{- 3}

(6.8 \cdot 1 0^{- 5}) \cdot (0.12)

What is e^{-1/2 (1/2)^2 1/2} ?
The solution to e^{-1/2 (1/2)^2 1/2} is 1/(\sqrt[16]{e)}