What is 4(4*0^4-12*0^2+3)e^{-0^2} ?

The solution to 4(4*0^4-12*0^2+3)e^{-0^2} is 12

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simplify 4(40^4-120^2+3)e^{-0^2}

simplify

4 (4 \cdot 0^{4} - 12 \cdot 0^{2} + 3) e^{- 0^{2}}

12

Solution steps

4 (4 \cdot 0^{4} - 12 \cdot 0^{2} + 3) e^{- 0^{2}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 4 \cdot \frac{1}{e ^{0^{2}}} (0^{4} \cdot 4 + 3 - 0^{2} \cdot 12)

Apply rule

0^{a} = 0

0^{4} = 0, 0^{2} = 0

= 4 \cdot \frac{1}{e ^{0}} (4 \cdot 0 + 3 - 12 \cdot 0)

Apply rule

0 \cdot a = 0

= 4 \cdot \frac{1}{e ^{0}} (0 + 3 - 0)

\frac{1}{e ^{0}} = 1

= 4 \cdot 1 \cdot (0 + 3 - 0)

Add/Subtract the numbers:

0 - 0 + 3 = 3

= 4 \cdot 3 \cdot 1

Multiply the numbers:

4 \cdot 3 \cdot 1 = 12

= 12

(e^{- 2 x}) (\frac{1}{2} e^{- x} + \frac{1}{2} e^{2 x})

e^{- 2} \cdot e^{3}

(1 + x)^{- \frac{3}{2}}

e^{\frac{- x ^{2}}{2}} \cdot e^{\frac{- x ^{2}}{2}}

3.7 e^{4} \cdot 5.2 e^{- 5}

What is 4(4*0^4-12*0^2+3)e^{-0^2} ?
The solution to 4(4*0^4-12*0^2+3)e^{-0^2} is 12