What is ((f^2-q^2)/(fq)}{\frac{f-q)/q} ?

The solution to ((f^2-q^2)/(fq)}{\frac{f-q)/q} is (f+q)/f

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simplify ((f^2-q^2)/(fq)}{\frac{f-q)/q}

simplify

\frac{\frac{f ^{2} - q ^{2}}{f q}}{\frac{f - q}{q}}

\frac{f + q}{f}

Solution steps

\frac{\frac{f ^{2} - q ^{2}}{f q}}{\frac{f - q}{q}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( f ^{2} - q ^{2} ) q}{f q ( f - q )}

Cancel the common factor:

q

= \frac{f ^{2} - q ^{2}}{f ( f - q )}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

f^{2} - q^{2} = (f + q) (f - q)

= \frac{( f + q ) ( f - q )}{f ( f - q )}

Cancel the common factor:

f - q

= \frac{f + q}{f}

n^{2} + 34 + 225

50 x^{2} - 18

x^{2} + 6 x = 9

- 7 x + 9 = 2 x - 99

\frac{3}{5} \cdot \frac{1}{7}

What is ((f^2-q^2)/(fq)}{\frac{f-q)/q} ?
The solution to ((f^2-q^2)/(fq)}{\frac{f-q)/q} is (f+q)/f