What are the solutions to the equation x^2+x-272=0 ?

The solutions to the equation x^2+x-272=0 are x=16,x=-17

Find the zeros of x^2+x-272=0

The zeros of x^2+x-272=0 are x=16,x=-17

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x^{2} + x - 272 = 0

x = 16, x = - 17

Solution steps

x^{2} + x - 272 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 272 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 272) = 33

x_{1, 2} = \frac{- 1 \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 33}{2 \cdot 1}, x_{2} = \frac{- 1 - 33}{2 \cdot 1}

x = \frac{- 1 + 33}{2 \cdot 1} : 16

x = \frac{- 1 - 33}{2 \cdot 1} : - 17

The solutions to the quadratic equation are:

x = 16, x = - 17

5 y^{3} + 3 y^{2} + 12 y

\frac{2}{x} - \frac{2}{y}

y^{2} + 2 y + 2 = 0

x^{2} - x = 0

2^{n} - 2^{n - 1}

What are the solutions to the equation x^2+x-272=0 ?
The solutions to the equation x^2+x-272=0 are x=16,x=-17
Find the zeros of x^2+x-272=0
The zeros of x^2+x-272=0 are x=16,x=-17