What is 1/2 (1.673*10^{-27})((604)^2) ?

The solution to 1/2 (1.673*10^{-27})((604)^2) is 604^2*(1673)/(10^{27)*2000}

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simplify 1/2 (1.673*10^{-27})((604)^2)

simplify

\frac{1}{2} (1.673 \cdot 1 0^{- 27}) ((604)^{2})

60 4^{2} \cdot \frac{1673}{1 0 ^{27} \cdot 2000}

Decimal Notation

0

Solution steps

\frac{1}{2} (1.673 \cdot 1 0^{- 27}) (60 4^{2})

Apply rule:

(a) = a

(60 4^{2}) = 60 4^{2}

= \frac{1}{2} \cdot 1.673 \cdot 1 0^{- 27} \cdot 60 4^{2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 27} = \frac{1}{1 0 ^{27}}

= \frac{1}{2} \cdot 1.673 \cdot \frac{1}{1 0 ^{27}} \cdot 60 4^{2}

1.673 = \frac{1673}{1000}

= \frac{1}{2} \cdot \frac{1673}{1000} \cdot \frac{1}{1 0 ^{27}} \cdot 60 4^{2}

\frac{1}{2} \cdot \frac{1673}{1000} \cdot \frac{1}{1 0 ^{27}} \cdot 60 4^{2} = \frac{1673}{1 0 ^{27} \cdot 2000} \cdot 60 4^{2}

= \frac{1673}{1 0 ^{27} \cdot 2000} \cdot 60 4^{2}

= 60 4^{2} \cdot \frac{1673}{1 0 ^{27} \cdot 2000}

(f g \circ f) (\frac{3 x - 2}{5})^{3}

\frac{1}{2 \cdot π} \cdot e^{- 0.5 \cdot 0}

1.28 x 1 0^{- 5} \cdot \frac{180}{π}

11.82 \cdot 1 0^{- 6}

e^{- 2 l n (1 - y)}

What is 1/2 (1.673*10^{-27})((604)^2) ?
The solution to 1/2 (1.673*10^{-27})((604)^2) is 604^2*(1673)/(10^{27)*2000}