What is (y^{-1}e^{2y})(2xy-e^{-2y}) ?

The solution to (y^{-1}e^{2y})(2xy-e^{-2y}) is (e^{2y}(2yx-e^{-2y}))/y

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simplify (y^{-1}e^{2y})(2xy-e^{-2y})

simplify

(y^{- 1} e^{2 y}) (2 x y - e^{- 2 y})

\frac{e ^{2 y} ( 2 y x - e ^{- 2 y} )}{y}

Solution steps

(y^{- 1} e^{2 y}) (2 x y - e^{- 2 y})

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= e^{2 y} \frac{1}{y} (2 y x - e^{- 2 y})

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot e ^{2 y} ( 2 x y - e ^{- 2 y} )}{y}

Multiply:

1 \cdot e^{2 y} = e^{2 y}

= \frac{e ^{2 y} ( 2 y x - e ^{- 2 y} )}{y}

\frac{0.01}{( 0.207 ) ^{2}} \cdot 6.69 \cdot 1 0^{- 7}

3 \cdot e^{- 7500 \cdot 0.0001}

8.854 \cdot 1 0^{- 12} \cdot \frac{π}{0.025}

(234349.59507) (0.01958) (8.854 \cdot 1 0^{- 12})

x \cdot \frac{yz}{2 ( e + x )}

What is (y^{-1}e^{2y})(2xy-e^{-2y}) ?
The solution to (y^{-1}e^{2y})(2xy-e^{-2y}) is (e^{2y}(2yx-e^{-2y}))/y