What are the solutions to the equation 0.6x^2-2.4x-0.6=0 ?

The solutions to the equation 0.6x^2-2.4x-0.6=0 are x=2+sqrt(5),x=2-sqrt(5)

Find the zeros of 0.6x^2-2.4x-0.6=0

The zeros of 0.6x^2-2.4x-0.6=0 are x=2+sqrt(5),x=2-sqrt(5)

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0.6 x^{2} - 2.4 x - 0.6 = 0

x = 2 + 5, x = 2 - 5

Solution steps

0.6 x^{2} - 2.4 x - 0.6 = 0

Multiply both sides by

10

6 x^{2} - 24 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 6 ( - 6 )}{2 \cdot 6}

(- 24)^{2} - 4 \cdot 6 (- 6) = 125

x_{1, 2} = \frac{- ( - 24 ) \pm 12 5}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12 5}{2 \cdot 6}, x_{2} = \frac{- ( - 24 ) - 12 5}{2 \cdot 6}

x = \frac{- ( - 24 ) + 12 5}{2 \cdot 6} : 2 + 5

x = \frac{- ( - 24 ) - 12 5}{2 \cdot 6} : 2 - 5

The solutions to the quadratic equation are:

x = 2 + 5, x = 2 - 5

\frac{x ^{- 6}}{x ^{- 4}}

0 = x^{2} - 41 x + 238

\frac{- 9 x y ^{5} z ^{3}}{36 x y ^{4} z ^{5}}

5 x (8 - x) = 10

\frac{x}{3} \leq x + 2

What are the solutions to the equation 0.6x^2-2.4x-0.6=0 ?
The solutions to the equation 0.6x^2-2.4x-0.6=0 are x=2+sqrt(5),x=2-sqrt(5)
Find the zeros of 0.6x^2-2.4x-0.6=0
The zeros of 0.6x^2-2.4x-0.6=0 are x=2+sqrt(5),x=2-sqrt(5)