What is 8.85(10^{-12})((2.25)/((1*10^{-4))}) ?

The solution to 8.85(10^{-12})((2.25)/((1*10^{-4))}) is 1593/8000000000

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simplify 8.85(10^{-12})((2.25)/((1*10^{-4))})

simplify

8.85 (1 0^{- 12}) (\frac{2.25}{( 1 \cdot 1 0 ^{- 4} )})

\frac{1593}{8000000000}

Decimal Notation

1.99125 E - 7

Solution steps

8.85 (1 0^{- 12}) (\frac{2.25}{1 \cdot 1 0 ^{- 4}})

\frac{2.25}{1 \cdot 1 0 ^{- 4}} = \frac{225}{100 \cdot 1 0 ^{- 4}}

= 8.85 \cdot 1 0^{- 12} \cdot \frac{225}{100 \cdot 1 0 ^{- 4}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 12} = \frac{1}{1 0 ^{12}}

= 8.85 \cdot \frac{1}{1 0 ^{12}} \cdot \frac{225}{100 \cdot 1 0 ^{- 4}}

Cancel

\frac{225}{100 \cdot 1 0 ^{- 4}} : 22500

= 8.85 \cdot \frac{1}{1 0 ^{12}} \cdot 22500

8.85 \cdot \frac{1}{1 0 ^{12}} \cdot 22500 = \frac{1593}{8000000000}

= \frac{1593}{8000000000}

p a rc ia l es \frac{9}{x ^{2} - 3 x}

e^{- e^{l n (x)}}

R^{2} + (\frac{h}{2})^{2}^{2} \cdot h \cdot π

(25 x^{2 y}) (10 x y^{2})

1000 \cdot 7.41 \cdot (1 0^{- 4}) \cdot 9.8

What is 8.85(10^{-12})((2.25)/((1*10^{-4))}) ?
The solution to 8.85(10^{-12})((2.25)/((1*10^{-4))}) is 1593/8000000000