What is (3^{2019+2})/(3^{2019-1)} ?

The solution to (3^{2019+2})/(3^{2019-1)} is 27

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simplify (3^{2019+2})/(3^{2019-1)}

simplify

\frac{3 ^{2019 + 2}}{3 ^{2019 - 1}}

27

Solution steps

\frac{3 ^{2019 + 2}}{3 ^{2019 - 1}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

= 3^{2019 + 2 - (2019 - 1)}

Subtract the numbers:

2019 - 1 = 2018

= 3^{2019 + 2 - 2018}

Add/Subtract the numbers:

2019 + 2 - 2018 = 3

= 3^{3}

3^{3} = 27

= 27

(- 1.88 + 4)^{2} (- 1.88 - 6)^{2}

(x + d e lt a x)^{- 1}

e^{- (\frac{l n ( k )}{( k - 1 )})}

What is (3^{2019+2})/(3^{2019-1)} ?
The solution to (3^{2019+2})/(3^{2019-1)} is 27